Faustino Mellerson: Car A gains 10 miles / hour on Car B10 miles / hour = 10 miles / 60 minutes = 1 miles / 6 minutesit will make up the 1 mile difference in 6 minutes
Gaston Edgcomb: 6 mins since rel. velocity is 50-40=10mph=>rel velocity=displacement/time.........displacement is 0=>time=1/10 hours or 6 minutes
Wilbert Shellgren: A: x=vt x = 50t => t = x/50B: x-1 = vt x-1 = 40t => t = (x-1) / 40x/50 = (x-1) / 40 =>40x = 50x - 50 =>10x = 50 =>x = 5.0 mileSo after 5 mile they pass each other.But that was not the question I see nowThe answer: t = x/50 = 5/50 = 0.1 hour = 6 min...Show more
Bethany Blocker: Difference between cars = 1 MileRelative speed = 50 (Car A) - 40 (Car B) . . . . . . . . . . = 10 Miles/HrTime Required = 1 / 10 Hrs . . . . . . . . . . = (1 / 10) * 60 Minutes . . . . . . . . . . = 6 MinutesYes.. You have done !...Show more
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